What is 2/3 (3x-1)>= 3/2 (2x-3) ?

The solution to 2/3 (3x-1)>= 3/2 (2x-3) is x<= 23/6

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2/3 (3x-1)>= 3/2 (2x-3)

\frac{2}{3} (3 x - 1) \geq \frac{3}{2} (2 x - 3)

x \leq \frac{23}{6}

Interval Notation

(- \infty, \frac{23}{6}]

Decimal Notation

x \leq 3.83333 \dots

Solution steps

\frac{2}{3} (3 x - 1) \geq \frac{3}{2} (2 x - 3)

Expand

\frac{2}{3} (3 x - 1) : 2 x - \frac{2}{3}

Expand

\frac{3}{2} (2 x - 3) : 3 x - \frac{9}{2}

2 x - \frac{2}{3} \geq 3 x - \frac{9}{2}

Move

\frac{2}{3}

to the right side

2 x \geq 3 x - \frac{23}{6}

Move

3 x

to the left side

- x \geq - \frac{23}{6}

Multiply both sides by

- 1

x \leq \frac{23}{6}

97 + 63

\frac{x ^{2} + x}{2} = \frac{8 x - 7}{3}

6 + 5

(x - 8)^{2} = 16

\frac{x - 4}{x - 6} \geq 1

What is 2/3 (3x-1)>= 3/2 (2x-3) ?
The solution to 2/3 (3x-1)>= 3/2 (2x-3) is x<= 23/6