What are the solutions to the equation -x^2+4x=-47 ?

The solutions to the equation -x^2+4x=-47 are x=2-sqrt(51),x=2+sqrt(51)

Find the zeros of -x^2+4x=-47

The zeros of -x^2+4x=-47 are x=2-sqrt(51),x=2+sqrt(51)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 4 x = - 47

x = 2 - 51, x = 2 + 51

Decimal Notation

x = - 5.14142 \dots, x = 9.14142 \dots

Solution steps

- x^{2} + 4 x = - 47

Move

47

to the left side

- x^{2} + 4 x + 47 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 47}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 47 = 251

x_{1, 2} = \frac{- 4 \pm 2 51}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 51}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 51}{2 ( - 1 )}

x = \frac{- 4 + 2 51}{2 ( - 1 )} : 2 - 51

x = \frac{- 4 - 2 51}{2 ( - 1 )} : 2 + 51

The solutions to the quadratic equation are:

x = 2 - 51, x = 2 + 51

x + 5 = 7

12 = x 2

3 x^{2} - 9 x - 12 = 0

- \frac{( 2 ) ^{3}}{3} + \frac{( 2 ) ^{2}}{2} + 2 (2)

2 (1 - 5 z) + 3 = 17

What are the solutions to the equation -x^2+4x=-47 ?
The solutions to the equation -x^2+4x=-47 are x=2-sqrt(51),x=2+sqrt(51)
Find the zeros of -x^2+4x=-47
The zeros of -x^2+4x=-47 are x=2-sqrt(51),x=2+sqrt(51)