What are the solutions to the equation 4x(x+6)=6 ?

The solutions to the equation 4x(x+6)=6 are x=(-6+sqrt(42))/2 ,x=-(6+sqrt(42))/2

Find the zeros of 4x(x+6)=6

The zeros of 4x(x+6)=6 are x=(-6+sqrt(42))/2 ,x=-(6+sqrt(42))/2

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4 x (x + 6) = 6

x = \frac{- 6 + 42}{2}, x = - \frac{6 + 42}{2}

Decimal Notation

x = 0.24037 \dots, x = - 6.24037 \dots

Solution steps

4 x (x + 6) = 6

Expand

4 x (x + 6) : 4 x^{2} + 24 x

4 x^{2} + 24 x = 6

Move

6

to the left side

4 x^{2} + 24 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

2 4^{2} - 4 \cdot 4 (- 6) = 442

x_{1, 2} = \frac{- 24 \pm 4 42}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 24 + 4 42}{2 \cdot 4}, x_{2} = \frac{- 24 - 4 42}{2 \cdot 4}

x = \frac{- 24 + 4 42}{2 \cdot 4} : \frac{- 6 + 42}{2}

x = \frac{- 24 - 4 42}{2 \cdot 4} : - \frac{6 + 42}{2}

The solutions to the quadratic equation are:

x = \frac{- 6 + 42}{2}, x = - \frac{6 + 42}{2}

6 x^{3} - 15 x^{2} < 0

\frac{- 5}{2} + 3

lo g_{\frac{1}{7}} (49)

(4 x + 3) (x + 2) = 3

\frac{4 !}{2 !}

What are the solutions to the equation 4x(x+6)=6 ?
The solutions to the equation 4x(x+6)=6 are x=(-6+sqrt(42))/2 ,x=-(6+sqrt(42))/2
Find the zeros of 4x(x+6)=6
The zeros of 4x(x+6)=6 are x=(-6+sqrt(42))/2 ,x=-(6+sqrt(42))/2