What are the solutions to the equation 7t=2t^2 ?

The solutions to the equation 7t=2t^2 are t=0,t= 7/2

Find the zeros of 7t=2t^2

The zeros of 7t=2t^2 are t=0,t= 7/2

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7 t = 2 t^{2}

t = 0, t = \frac{7}{2}

Decimal Notation

t = 0, t = 3.5

Solution steps

7 t = 2 t^{2}

Move

2 t^{2}

to the left side

7 t - 2 t^{2} = 0

Factor

7 t - 2 t^{2} : - t (2 t - 7)

- t (2 t - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t = 0 or 2 t - 7 = 0

Solve

2 t - 7 = 0 : t = \frac{7}{2}

The solutions to the quadratic equation are:

t = 0, t = \frac{7}{2}

4 5^{- \frac{3}{2}} \cdot 4 5^{2}

∣ 3 x - 4 ∣ + 2 = 8

∣ x - 3 ∣ = 12

2 ln (+ 1)

What are the solutions to the equation 7t=2t^2 ?
The solutions to the equation 7t=2t^2 are t=0,t= 7/2
Find the zeros of 7t=2t^2
The zeros of 7t=2t^2 are t=0,t= 7/2