What are the solutions to the equation (z+3)^2=-10 ?

The solutions to the equation (z+3)^2=-10 are z=sqrt(10)i-3,z=-sqrt(10)i-3

Find the zeros of (z+3)^2=-10

The zeros of (z+3)^2=-10 are z=sqrt(10)i-3,z=-sqrt(10)i-3

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(z + 3)^{2} = - 10

z = 10 i - 3, z = - 10 i - 3

Solution steps

(z + 3)^{2} = - 10

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 3 = - 10 : z = 10 i - 3

Solve

z + 3 = - - 10 : z = - 10 i - 3

The solutions to the quadratic equation are:

z = 10 i - 3, z = - 10 i - 3

9^{- \frac{3}{2}}

2 \cdot \frac{5}{12}

- 2 (2 x - 3) = 3 (x + 1) + 10

\frac{\frac{8}{9} + \frac{1}{5}}{\frac{5}{6} + \frac{1}{2}}

4 x^{2} = 2 x^{2}

What are the solutions to the equation (z+3)^2=-10 ?
The solutions to the equation (z+3)^2=-10 are z=sqrt(10)i-3,z=-sqrt(10)i-3
Find the zeros of (z+3)^2=-10
The zeros of (z+3)^2=-10 are z=sqrt(10)i-3,z=-sqrt(10)i-3