What are the solutions to the equation 3(x^2-1)-10=5 ?

The solutions to the equation 3(x^2-1)-10=5 are x=sqrt(6),x=-sqrt(6)

Find the zeros of 3(x^2-1)-10=5

The zeros of 3(x^2-1)-10=5 are x=sqrt(6),x=-sqrt(6)

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3 (x^{2} - 1) - 10 = 5

x = 6, x = - 6

Decimal Notation

x = 2.44948 \dots, x = - 2.44948 \dots

Solution steps

3 (x^{2} - 1) - 10 = 5

Move

10

to the right side

3 (x^{2} - 1) = 15

Divide both sides by

3

x^{2} - 1 = 5

Move

1

to the right side

x^{2} = 6

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 6, x = - 6

∣ 4 x + 3 ∣ - 4 \leq 11

n^{2} + 8 n + 12

\frac{x - 7}{x + 1} \geq 0

x^{3} - 5 x^{2} - 6 x \leq 0

\frac{222 π}{180} - \frac{5 π}{4}

What are the solutions to the equation 3(x^2-1)-10=5 ?
The solutions to the equation 3(x^2-1)-10=5 are x=sqrt(6),x=-sqrt(6)
Find the zeros of 3(x^2-1)-10=5
The zeros of 3(x^2-1)-10=5 are x=sqrt(6),x=-sqrt(6)