What are the solutions to the equation 6+5x-x^2=6-x ?

The solutions to the equation 6+5x-x^2=6-x are x=0,x=6

Find the zeros of 6+5x-x^2=6-x

The zeros of 6+5x-x^2=6-x are x=0,x=6

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6 + 5 x - x^{2} = 6 - x

x = 0, x = 6

Solution steps

6 + 5 x - x^{2} = 6 - x

Move

x

to the left side

- x^{2} + 6 x + 6 = 6

Move

6

to the left side

- x^{2} + 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

6^{2} - 4 (- 1) \cdot 0 = 6

x_{1, 2} = \frac{- 6 \pm 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 6}{2 ( - 1 )}, x_{2} = \frac{- 6 - 6}{2 ( - 1 )}

x = \frac{- 6 + 6}{2 ( - 1 )} : 0

x = \frac{- 6 - 6}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = 0, x = 6

3 - \frac{x}{3} > - 4

9 x - 8 < 28

m^{2} - 5 m + 4

- 8 - 3

\frac{1 0 ^{3}}{1 0 ^{5}}

What are the solutions to the equation 6+5x-x^2=6-x ?
The solutions to the equation 6+5x-x^2=6-x are x=0,x=6
Find the zeros of 6+5x-x^2=6-x
The zeros of 6+5x-x^2=6-x are x=0,x=6