What is (x+2)(x-1)(x-3)<= 0 ?

The solution to (x+2)(x-1)(x-3)<= 0 is x<=-2\lor 1<= x<= 3

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(x+2)(x-1)(x-3)<= 0

(x + 2) (x - 1) (x - 3) \leq 0

x \leq - 2 or 1 \leq x \leq 3

Interval Notation

(- \infty, - 2] \cup [1, 3]

Solution steps

(x + 2) (x - 1) (x - 3) \leq 0

Identify the intervals

x \leq - 2 or 1 \leq x \leq 3

6 x^{2} + 3 x - 12 = 0

12 a^{4} + 8 a

- (4 + h) = 3 h

1 6^{- \frac{2}{3}}

What is (x+2)(x-1)(x-3)<= 0 ?
The solution to (x+2)(x-1)(x-3)<= 0 is x<=-2\lor 1<= x<= 3