What are the solutions to the equation x^2+10x+26=0 ?

The solutions to the equation x^2+10x+26=0 are x=-5+i,x=-5-i

Find the zeros of x^2+10x+26=0

The zeros of x^2+10x+26=0 are x=-5+i,x=-5-i

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x^{2} + 10 x + 26 = 0

x = - 5 + i, x = - 5 - i

Solution steps

x^{2} + 10 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 26}{2 \cdot 1}

Simplify

1 0^{2} - 4 \cdot 1 \cdot 26 : 2 i

x_{1, 2} = \frac{- 10 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 i}{2 \cdot 1}

x = \frac{- 10 + 2 i}{2 \cdot 1} : - 5 + i

x = \frac{- 10 - 2 i}{2 \cdot 1} : - 5 - i

The solutions to the quadratic equation are:

x = - 5 + i, x = - 5 - i

7^{3}

\frac{u}{5} 2.6 = 3.8

6 4^{- \frac{1}{3}}

- 36 x^{2} + 168 x - 120

\frac{3}{4} (- 8)^{\frac{4}{3}}

What are the solutions to the equation x^2+10x+26=0 ?
The solutions to the equation x^2+10x+26=0 are x=-5+i,x=-5-i
Find the zeros of x^2+10x+26=0
The zeros of x^2+10x+26=0 are x=-5+i,x=-5-i