What are the solutions to the equation h^2+22.4h=1837 ?

The solutions to the equation h^2+22.4h=1837 are h=(-56+sqrt(49061))/5 ,h=-(56+sqrt(49061))/5

Find the zeros of h^2+22.4h=1837

The zeros of h^2+22.4h=1837 are h=(-56+sqrt(49061))/5 ,h=-(56+sqrt(49061))/5

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h^{2} + 22.4 h = 1837

h = \frac{- 56 + 49061}{5}, h = - \frac{56 + 49061}{5}

Decimal Notation

h = 33.09943 \dots, h = - 55.49943 \dots

Solution steps

h^{2} + 22.4 h = 1837

Multiply both sides by

10

10 h^{2} + 224 h = 18370

Move

18370

to the left side

10 h^{2} + 224 h - 18370 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 224 \pm 22 4 ^{2} - 4 \cdot 10 ( - 18370 )}{2 \cdot 10}

22 4^{2} - 4 \cdot 10 (- 18370) = 449061

h_{1, 2} = \frac{- 224 \pm 4 49061}{2 \cdot 10}

Separate the solutions

h_{1} = \frac{- 224 + 4 49061}{2 \cdot 10}, h_{2} = \frac{- 224 - 4 49061}{2 \cdot 10}

h = \frac{- 224 + 4 49061}{2 \cdot 10} : \frac{- 56 + 49061}{5}

h = \frac{- 224 - 4 49061}{2 \cdot 10} : - \frac{56 + 49061}{5}

The solutions to the quadratic equation are:

h = \frac{- 56 + 49061}{5}, h = - \frac{56 + 49061}{5}

216 x^{3} - 64

\frac{1}{x ^{2} - 4} \leq 0

a^{2} + 2 a - 48

28

2 z + \frac{1}{2} \leq \frac{3}{2}

What are the solutions to the equation h^2+22.4h=1837 ?
The solutions to the equation h^2+22.4h=1837 are h=(-56+sqrt(49061))/5 ,h=-(56+sqrt(49061))/5
Find the zeros of h^2+22.4h=1837
The zeros of h^2+22.4h=1837 are h=(-56+sqrt(49061))/5 ,h=-(56+sqrt(49061))/5