What are the solutions to the equation -3=4x^2+6x+3 ?

The solutions to the equation -3=4x^2+6x+3 are x=-3/4+i(sqrt(15))/4 ,x=-3/4-i(sqrt(15))/4

Find the zeros of -3=4x^2+6x+3

The zeros of -3=4x^2+6x+3 are x=-3/4+i(sqrt(15))/4 ,x=-3/4-i(sqrt(15))/4

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- 3 = 4 x^{2} + 6 x + 3

x = - \frac{3}{4} + i \frac{15}{4}, x = - \frac{3}{4} - i \frac{15}{4}

Solution steps

- 3 = 4 x^{2} + 6 x + 3

Switch sides

4 x^{2} + 6 x + 3 = - 3

Move

3

to the left side

4 x^{2} + 6 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

Simplify

6^{2} - 4 \cdot 4 \cdot 6 : 215 i

x_{1, 2} = \frac{- 6 \pm 2 15 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 6 + 2 15 i}{2 \cdot 4}, x_{2} = \frac{- 6 - 2 15 i}{2 \cdot 4}

x = \frac{- 6 + 2 15 i}{2 \cdot 4} : - \frac{3}{4} + i \frac{15}{4}

x = \frac{- 6 - 2 15 i}{2 \cdot 4} : - \frac{3}{4} - i \frac{15}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{4} + i \frac{15}{4}, x = - \frac{3}{4} - i \frac{15}{4}

- 12 = 6 x + 18 - 9 x

s - 2 \leq 7

- 5 x^{2} = 0

16 - x^{8}

75 + 48

What are the solutions to the equation -3=4x^2+6x+3 ?
The solutions to the equation -3=4x^2+6x+3 are x=-3/4+i(sqrt(15))/4 ,x=-3/4-i(sqrt(15))/4
Find the zeros of -3=4x^2+6x+3
The zeros of -3=4x^2+6x+3 are x=-3/4+i(sqrt(15))/4 ,x=-3/4-i(sqrt(15))/4