What are the solutions to the equation x^2-4x+4=4 ?

The solutions to the equation x^2-4x+4=4 are x=4,x=0

Find the zeros of x^2-4x+4=4

The zeros of x^2-4x+4=4 are x=4,x=0

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x^{2} - 4 x + 4 = 4

x = 4, x = 0

Solution steps

x^{2} - 4 x + 4 = 4

Move

4

to the left side

x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

x = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

- 2 x - 4 = x + 2

x^{2} + 5 x - 3 = 3

x^{3} - 5 x^{2} - 2 x + 24

62 \cdot 814

a c + b c - a d - b d

What are the solutions to the equation x^2-4x+4=4 ?
The solutions to the equation x^2-4x+4=4 are x=4,x=0
Find the zeros of x^2-4x+4=4
The zeros of x^2-4x+4=4 are x=4,x=0