What is factor x^3-4x+2x^2-8 ?

The solution to factor x^3-4x+2x^2-8 is (x+2)^2(x-2)

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factor x^3-4x+2x^2-8

factor

x^{3} - 4 x + 2 x^{2} - 8

(x + 2)^{2} (x - 2)

Solution steps

x^{3} - 4 x + 2 x^{2} - 8

Write in the standard form

= x^{3} + 2 x^{2} - 4 x - 8

= (x^{3} + 2 x^{2}) + (- 4 x - 8)

Factor out

x^{2}

from

x^{3} + 2 x^{2} : x^{2} (x + 2)

Factor out

- 4

from

- 4 x - 8 : - 4 (x + 2)

= x^{2} (x + 2) - 4 (x + 2)

Factor out common term

x + 2

= (x + 2) (x^{2} - 4)

Factor

x^{2} - 4 : (x + 2) (x - 2)

= (x + 2) (x + 2) (x - 2)

Apply exponent rule:

aa = a^{2}

(x + 2) (x + 2) = (x + 2)^{2}

= (x + 2)^{2} (x - 2)

13 (n + 12) - 10 n

[4 a - 9] < 10

2 (3 + 6 k) = 14

\frac{( 6 - 4 i )}{( 1 - i )}

∣ - 7 ∣

What is factor x^3-4x+2x^2-8 ?
The solution to factor x^3-4x+2x^2-8 is (x+2)^2(x-2)