What is (4x+6)/5 >= (8x-8)/6 ?

The solution to (4x+6)/5 >= (8x-8)/6 is x<= 19/4

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(4x+6)/5 >= (8x-8)/6

\frac{4 x + 6}{5} \geq \frac{8 x - 8}{6}

x \leq \frac{19}{4}

Solution steps

\frac{4 x + 6}{5} \geq \frac{8 x - 8}{6}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(4 x + 6) \cdot 6 \geq 5 (8 x - 8)

Expand

(4 x + 6) \cdot 6 : 24 x + 36

Expand

5 (8 x - 8) : 40 x - 40

24 x + 36 \geq 40 x - 40

Move

36

to the right side

24 x \geq 40 x - 76

Move

40 x

to the left side

- 16 x \geq - 76

Multiply both sides by

- 1

16 x \leq 76

Divide both sides by

16

x \leq \frac{19}{4}

6 = \frac{3 x - 1}{2} \cdot 2.4

8 1^{\frac{- 1}{2}}

\frac{2}{3} x < 2

v - 24 \leq 30

7 \cdot 105