What are the solutions to the equation x/3*(x-1)-x/4*(x+1)+(3x+4)/(12)=0 ?

The solutions to the equation x/3*(x-1)-x/4*(x+1)+(3x+4)/(12)=0 are x=2

Find the zeros of x/3*(x-1)-x/4*(x+1)+(3x+4)/(12)=0

The zeros of x/3*(x-1)-x/4*(x+1)+(3x+4)/(12)=0 are x=2

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\frac{x}{3} \cdot (x - 1) - \frac{x}{4} \cdot (x + 1) + \frac{3 x + 4}{12} = 0

x = 2

Solution steps

\frac{x}{3} (x - 1) - \frac{x}{4} (x + 1) + \frac{3 x + 4}{12} = 0

Find Least Common Multiplier of

3, 4, 12 : 12

Multiply by LCM=

12

\frac{x}{3} (x - 1) \cdot 12 - \frac{x}{4} (x + 1) \cdot 12 + \frac{3 x + 4}{12} \cdot 12 = 0 \cdot 12

Simplify

4 x (x - 1) - 3 x (x + 1) + 3 x + 4 = 0

Expand

4 x (x - 1) - 3 x (x + 1) + 3 x + 4 : x^{2} - 4 x + 4

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

∣ 2 x + 4 ∣ \leq 14

2 x^{2} - 4 x - 30

3 x = - 4 x - 35

x^{2} - 100 = 0

2 x^{2} - 12 x + 5 = 0

What are the solutions to the equation x/3*(x-1)-x/4*(x+1)+(3x+4)/(12)=0 ?
The solutions to the equation x/3*(x-1)-x/4*(x+1)+(3x+4)/(12)=0 are x=2
Find the zeros of x/3*(x-1)-x/4*(x+1)+(3x+4)/(12)=0
The zeros of x/3*(x-1)-x/4*(x+1)+(3x+4)/(12)=0 are x=2