What is factor 2x^2+11x-40 ?

The solution to factor 2x^2+11x-40 is (2x-5)(x+8)

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factor 2x^2+11x-40

factor

2 x^{2} + 11 x - 40

(2 x - 5) (x + 8)

Solution steps

2 x^{2} + 11 x - 40

Break the expression into groups

= (2 x^{2} - 5 x) + (16 x - 40)

Factor out

x

from

2 x^{2} - 5 x : x (2 x - 5)

Factor out

8

from

16 x - 40 : 8 (2 x - 5)

= x (2 x - 5) + 8 (2 x - 5)

Factor out common term

2 x - 5

= (2 x - 5) (x + 8)

∣ 2 x - 7 ∣ = 15

\frac{a + 3}{a ^{2} - 1} + \frac{a - 1}{2 a + 2} + \frac{a - 4}{4 a - 4}

f (m) = \frac{2 m ^{6} + 6 m}{3 m ^{14} + 12 m ^{9} + 9 m ^{4}}

10 (1 + 0.4)^{5}

ln (x - 1) < 1