What are the solutions to the equation -16x^2+49=0 ?

The solutions to the equation -16x^2+49=0 are x= 7/4 ,x=-7/4

Find the zeros of -16x^2+49=0

The zeros of -16x^2+49=0 are x= 7/4 ,x=-7/4

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- 16 x^{2} + 49 = 0

x = \frac{7}{4}, x = - \frac{7}{4}

Decimal Notation

x = 1.75, x = - 1.75

Solution steps

- 16 x^{2} + 49 = 0

Move

49

to the right side

- 16 x^{2} = - 49

Divide both sides by

- 16

x^{2} = \frac{49}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{49}{16}, x = - \frac{49}{16}

\frac{49}{16} = \frac{7}{4}

- \frac{49}{16} = - \frac{7}{4}

x = \frac{7}{4}, x = - \frac{7}{4}

t^{3} - 3 t + 2

3 (x + 4) = - 18

\frac{100}{4}

- 3 ∣ y - 3 ∣ = 9

5 = 5 (x + 6)

What are the solutions to the equation -16x^2+49=0 ?
The solutions to the equation -16x^2+49=0 are x= 7/4 ,x=-7/4
Find the zeros of -16x^2+49=0
The zeros of -16x^2+49=0 are x= 7/4 ,x=-7/4