What are the solutions to the equation 2m^2+5=10m ?

The solutions to the equation 2m^2+5=10m are m=(5+sqrt(15))/2 ,m=(5-sqrt(15))/2

Find the zeros of 2m^2+5=10m

The zeros of 2m^2+5=10m are m=(5+sqrt(15))/2 ,m=(5-sqrt(15))/2

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2 m^{2} + 5 = 10 m

m = \frac{5 + 15}{2}, m = \frac{5 - 15}{2}

Decimal Notation

m = 4.43649 \dots, m = 0.56350 \dots

Solution steps

2 m^{2} + 5 = 10 m

Move

10 m

to the left side

2 m^{2} + 5 - 10 m = 0

Write in the standard form

a x^{2} + b x + c = 0

2 m^{2} - 10 m + 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 5 = 215

m_{1, 2} = \frac{- ( - 10 ) \pm 2 15}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- ( - 10 ) + 2 15}{2 \cdot 2}, m_{2} = \frac{- ( - 10 ) - 2 15}{2 \cdot 2}

m = \frac{- ( - 10 ) + 2 15}{2 \cdot 2} : \frac{5 + 15}{2}

m = \frac{- ( - 10 ) - 2 15}{2 \cdot 2} : \frac{5 - 15}{2}

The solutions to the quadratic equation are:

m = \frac{5 + 15}{2}, m = \frac{5 - 15}{2}

∣ 5 x - 7 ∣ = 4

\frac{( 2 x - 6 )}{x + 4} \leq 0

\frac{( - 5 ) ^{- 8}}{( - 5 ) ^{- 3}}

- 16 t^{2} + 144 = 0

\frac{∣ x - 1 ∣ - x}{1 - ∣ x ∣} \geq 0

What are the solutions to the equation 2m^2+5=10m ?
The solutions to the equation 2m^2+5=10m are m=(5+sqrt(15))/2 ,m=(5-sqrt(15))/2
Find the zeros of 2m^2+5=10m
The zeros of 2m^2+5=10m are m=(5+sqrt(15))/2 ,m=(5-sqrt(15))/2