What are the solutions to the equation 2x^2+4x+7=0 ?

The solutions to the equation 2x^2+4x+7=0 are x=-1+isqrt(5/2),x=-1-isqrt(5/2)

Find the zeros of 2x^2+4x+7=0

The zeros of 2x^2+4x+7=0 are x=-1+isqrt(5/2),x=-1-isqrt(5/2)

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2 x^{2} + 4 x + 7 = 0

x = - 1 + i \frac{5}{2}, x = - 1 - i \frac{5}{2}

Solution steps

2 x^{2} + 4 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

Simplify

4^{2} - 4 \cdot 2 \cdot 7 : 210 i

x_{1, 2} = \frac{- 4 \pm 2 10 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 2 10 i}{2 \cdot 2}, x_{2} = \frac{- 4 - 2 10 i}{2 \cdot 2}

x = \frac{- 4 + 2 10 i}{2 \cdot 2} : - 1 + i \frac{5}{2}

x = \frac{- 4 - 2 10 i}{2 \cdot 2} : - 1 - i \frac{5}{2}

The solutions to the quadratic equation are:

x = - 1 + i \frac{5}{2}, x = - 1 - i \frac{5}{2}

\frac{2}{3} x = 2

- 8 < 2 (x + 4)

13 x + 25 < - 1

8 x^{2} - 14 x - 9

(5 h + 2 k) (5 h - 2 k)

What are the solutions to the equation 2x^2+4x+7=0 ?
The solutions to the equation 2x^2+4x+7=0 are x=-1+isqrt(5/2),x=-1-isqrt(5/2)
Find the zeros of 2x^2+4x+7=0
The zeros of 2x^2+4x+7=0 are x=-1+isqrt(5/2),x=-1-isqrt(5/2)