What is -x^2>= 3-4x ?

The solution to -x^2>= 3-4x is 1<= x<= 3

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-x^2>= 3-4x

- x^{2} \geq 3 - 4 x

1 \leq x \leq 3

Interval Notation

[1, 3]

Solution steps

- x^{2} \geq 3 - 4 x

Rewrite in standard form

- x^{2} + 4 x - 3 \geq 0

Factor

- x^{2} + 4 x - 3 : - (x - 1) (x - 3)

- (x - 1) (x - 3) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x - 1) (x - 3)) (- 1) \leq 0 \cdot (- 1)

Simplify

(x - 1) (x - 3) \leq 0

Identify the intervals

1 \leq x \leq 3

2 x^{2} - 5 x - 12 = 0

2 - ∣ p + 2 ∣ = - 4

3 x + 7 x + 1 = 2 (5 x + 1) + 2

\frac{8}{2}

- 3 < 4 x - 9 < 11