What is (7-11i)/(1-3i) ?

The solution to (7-11i)/(1-3i) is 4+i

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simplify (7-11i)/(1-3i)

simplify

\frac{7 - 11 i}{1 - 3 i}

4 + i

Solution steps

\frac{7 - 11 i}{1 - 3 i}

Multiply by the conjugate

\frac{1 + 3 i}{1 + 3 i}

= \frac{( 7 - 11 i ) ( 1 + 3 i )}{( 1 - 3 i ) ( 1 + 3 i )}

Simplify

\frac{( 7 - 11 i ) ( 1 + 3 i )}{( 1 - 3 i ) ( 1 + 3 i )} : \frac{40 + 10 i}{10}

= \frac{40 + 10 i}{10}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{40}{10} + \frac{10}{10} i

Simplify

\frac{40}{10} + \frac{10}{10} i : 4 + i

= 4 + i

10 (h + 1) - 4 = 76

42 x^{4} z - 24 x^{5} y^{2} z^{3}

(3 b - 8) + (7 b + 4)

2 - 7

∣ w - 6 ∣ \geq 3