What are the solutions to the equation 64u^2+4=0 ?

The solutions to the equation 64u^2+4=0 are u= 1/4 i,u=-1/4 i

Find the zeros of 64u^2+4=0

The zeros of 64u^2+4=0 are u= 1/4 i,u=-1/4 i

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64 u^{2} + 4 = 0

u = \frac{1}{4} i, u = - \frac{1}{4} i

Solution steps

64 u^{2} + 4 = 0

Move

4

to the right side

64 u^{2} = - 4

Divide both sides by

64

u^{2} = - \frac{1}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = - \frac{1}{16}, u = - - \frac{1}{16}

- \frac{1}{16} = \frac{1}{4} i

- - \frac{1}{16} = - \frac{1}{4} i

u = \frac{1}{4} i, u = - \frac{1}{4} i

2 y - 6 y + 8 \leq 2 (- 2 y + 9)

559 + p = 525 + 559

a^{2} + 9 a + 18

\frac{\frac{5}{6}}{3}

2 x^{2} - 13 x + 20

What are the solutions to the equation 64u^2+4=0 ?
The solutions to the equation 64u^2+4=0 are u= 1/4 i,u=-1/4 i
Find the zeros of 64u^2+4=0
The zeros of 64u^2+4=0 are u= 1/4 i,u=-1/4 i