What are the solutions to the equation v^2+6v+1=0 ?

The solutions to the equation v^2+6v+1=0 are v=-3+2sqrt(2),v=-3-2sqrt(2)

Find the zeros of v^2+6v+1=0

The zeros of v^2+6v+1=0 are v=-3+2sqrt(2),v=-3-2sqrt(2)

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v^{2} + 6 v + 1 = 0

v = - 3 + 22, v = - 3 - 22

Decimal Notation

v = - 0.17157 \dots, v = - 5.82842 \dots

Solution steps

v^{2} + 6 v + 1 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 1 = 42

v_{1, 2} = \frac{- 6 \pm 4 2}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 6 + 4 2}{2 \cdot 1}, v_{2} = \frac{- 6 - 4 2}{2 \cdot 1}

v = \frac{- 6 + 4 2}{2 \cdot 1} : - 3 + 22

v = \frac{- 6 - 4 2}{2 \cdot 1} : - 3 - 22

The solutions to the quadratic equation are:

v = - 3 + 22, v = - 3 - 22

2 x^{2} + 3 x + 8 = 0

5 x + 30 y

\frac{2}{3} + \frac{1}{4}

\frac{c ^{2} - 9}{2 c + 6}

4 x^{2} - 12 x y + 5 y^{2}

What are the solutions to the equation v^2+6v+1=0 ?
The solutions to the equation v^2+6v+1=0 are v=-3+2sqrt(2),v=-3-2sqrt(2)
Find the zeros of v^2+6v+1=0
The zeros of v^2+6v+1=0 are v=-3+2sqrt(2),v=-3-2sqrt(2)