What are the solutions to the equation q^2+2q+1=0 ?

The solutions to the equation q^2+2q+1=0 are q=-1

Find the zeros of q^2+2q+1=0

The zeros of q^2+2q+1=0 are q=-1

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q^{2} + 2 q + 1 = 0

q = - 1

Solution steps

q^{2} + 2 q + 1 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

q_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

q = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

q = - 1

The solution to the quadratic equation is:

q = - 1

y 125 x^{5} y^{6}

(x + 8)^{2} - 6 (x + 8) - 16 = 0

x^{4} + x^{3} + x + 1

e^{- 3 l n ∣ x ∣}

\frac{1}{3} Y = \frac{3}{4}

What are the solutions to the equation q^2+2q+1=0 ?
The solutions to the equation q^2+2q+1=0 are q=-1
Find the zeros of q^2+2q+1=0
The zeros of q^2+2q+1=0 are q=-1