What are the solutions to the equation -2t^2+10t=0 ?

The solutions to the equation -2t^2+10t=0 are t=0,t=5

Find the zeros of -2t^2+10t=0

The zeros of -2t^2+10t=0 are t=0,t=5

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- 2 t^{2} + 10 t = 0

t = 0, t = 5

Solution steps

- 2 t^{2} + 10 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

1 0^{2} - 4 (- 2) \cdot 0 = 10

t_{1, 2} = \frac{- 10 \pm 10}{2 ( - 2 )}

Separate the solutions

t_{1} = \frac{- 10 + 10}{2 ( - 2 )}, t_{2} = \frac{- 10 - 10}{2 ( - 2 )}

t = \frac{- 10 + 10}{2 ( - 2 )} : 0

t = \frac{- 10 - 10}{2 ( - 2 )} : 5

The solutions to the quadratic equation are:

t = 0, t = 5

3 (- 2 x + 4) - 4 x - 2 = - 20

3^{2} + x^{2} = 7^{2}

\frac{3}{4} \cdot \frac{1}{5}

(x - 8)^{2} = 49

5 x^{2} + 23 x + 12

What are the solutions to the equation -2t^2+10t=0 ?
The solutions to the equation -2t^2+10t=0 are t=0,t=5
Find the zeros of -2t^2+10t=0
The zeros of -2t^2+10t=0 are t=0,t=5