What are the solutions to the equation (m+7)(m-8)=-14 ?

The solutions to the equation (m+7)(m-8)=-14 are m=7,m=-6

Find the zeros of (m+7)(m-8)=-14

The zeros of (m+7)(m-8)=-14 are m=7,m=-6

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(m + 7) (m - 8) = - 14

m = 7, m = - 6

Solution steps

(m + 7) (m - 8) = - 14

Expand

(m + 7) (m - 8) : m^{2} - m - 56

m^{2} - m - 56 = - 14

Move

14

to the left side

m^{2} - m - 42 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 42 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 42) = 13

m_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 13}{2 \cdot 1}, m_{2} = \frac{- ( - 1 ) - 13}{2 \cdot 1}

m = \frac{- ( - 1 ) + 13}{2 \cdot 1} : 7

m = \frac{- ( - 1 ) - 13}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

m = 7, m = - 6

2 x^{2} - (2 x + 1) = - 7

x^{2} - 14 x + 49 < 0

5 x^{3} + x^{2} - 20 x - 4

\frac{3}{4} - \frac{3}{5}

What are the solutions to the equation (m+7)(m-8)=-14 ?
The solutions to the equation (m+7)(m-8)=-14 are m=7,m=-6
Find the zeros of (m+7)(m-8)=-14
The zeros of (m+7)(m-8)=-14 are m=7,m=-6