What is the answer to |x^2+2x|=|4x+3| ?

The answer to |x^2+2x|=|4x+3| is x=-3-sqrt(6)\lor x=-1\lor x=-3+sqrt(6)\lor x=3

Solve for x: |x^2+2x|=|4x+3|

The solution is x=-3-sqrt(6)\lor x=-1\lor x=-3+sqrt(6)\lor x=3

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x^{2} + 2 x = ∣ 4 x + 3 ∣

x = - 3 - 6 or x = - 1 or x = - 3 + 6 or x = 3

Decimal Notation

x = - 5.44948 \dots, x = - 1, x = - 0.55051 \dots, x = 3

Solution steps

x^{2} + 2 x = ∣ 4 x + 3 ∣

Find positive and negative intervals

x \leq - 2, - 2 < x < - \frac{3}{4}, - \frac{3}{4} \leq x < 0, x \geq 0

Solve the inequality for each interval

x = - 3 - 6 or x = - 1 or x = - 3 + 6 or x = 3

- 3 + y < 6

\frac{( 4 - 2 x )}{3 x + 5} \leq 0

6 u^{2} \cdot (2 u - 5)^{2} - 12 u^{2} \cdot (2 u - 5) \cdot (u + 5)

\frac{- 18}{( - \frac{4}{9} )}

∣ x + 1 ∣ \leq 4

What is the answer to |x^2+2x|=|4x+3| ?
The answer to |x^2+2x|=|4x+3| is x=-3-sqrt(6)\lor x=-1\lor x=-3+sqrt(6)\lor x=3
Solve for x: |x^2+2x|=|4x+3|
The solution is x=-3-sqrt(6)\lor x=-1\lor x=-3+sqrt(6)\lor x=3