What are the solutions to the equation (x(x+4))/2 =96 ?

The solutions to the equation (x(x+4))/2 =96 are x=12,x=-16

Find the zeros of (x(x+4))/2 =96

The zeros of (x(x+4))/2 =96 are x=12,x=-16

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\frac{x ( x + 4 )}{2} = 96

x = 12, x = - 16

Solution steps

\frac{x ( x + 4 )}{2} = 96

Multiply both sides by

2

x (x + 4) = 192

Expand

x (x + 4) : x^{2} + 4 x

x^{2} + 4 x = 192

Move

192

to the left side

x^{2} + 4 x - 192 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 192 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 192) = 28

x_{1, 2} = \frac{- 4 \pm 28}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 28}{2 \cdot 1}, x_{2} = \frac{- 4 - 28}{2 \cdot 1}

x = \frac{- 4 + 28}{2 \cdot 1} : 12

x = \frac{- 4 - 28}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = 12, x = - 16

x^{2} y^{3} z^{4} \cdot x^{2} y^{3} z^{4}

x^{3} - 37 x + 6

2 (1 - x) + 4 (- 2 + 5 x) = 6 (1 - x)

6 x^{2} - 31 x + 35

3 \cdot (5 - 4) - 4 \cdot (5 - 4)

What are the solutions to the equation (x(x+4))/2 =96 ?
The solutions to the equation (x(x+4))/2 =96 are x=12,x=-16
Find the zeros of (x(x+4))/2 =96
The zeros of (x(x+4))/2 =96 are x=12,x=-16