What are the solutions to the equation x^2+32=12x ?

The solutions to the equation x^2+32=12x are x=8,x=4

Find the zeros of x^2+32=12x

The zeros of x^2+32=12x are x=8,x=4

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x^{2} + 32 = 12 x

x = 8, x = 4

Solution steps

x^{2} + 32 = 12 x

Move

12 x

to the left side

x^{2} + 32 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 12 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 32 = 4

x_{1, 2} = \frac{- ( - 12 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4}{2 \cdot 1} : 8

x = \frac{- ( - 12 ) - 4}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 8, x = 4

2 (x + 3) + 3 (x - 1) > 2 (x + 2)

\frac{x + 1}{2 x - 3} \geq \frac{x}{x - 1}

9 x^{2} + 30 x > - 25

2 x^{2} - 144 = 0

N^{4} + 5 N^{2} + 6

What are the solutions to the equation x^2+32=12x ?
The solutions to the equation x^2+32=12x are x=8,x=4
Find the zeros of x^2+32=12x
The zeros of x^2+32=12x are x=8,x=4