What are the solutions to the equation 15t^2+5t=0 ?

The solutions to the equation 15t^2+5t=0 are t=0,t=-1/3

Find the zeros of 15t^2+5t=0

The zeros of 15t^2+5t=0 are t=0,t=-1/3

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15 t^{2} + 5 t = 0

t = 0, t = - \frac{1}{3}

Decimal Notation

t = 0, t = - 0.33333 \dots

Solution steps

15 t^{2} + 5 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 15 \cdot 0}{2 \cdot 15}

5^{2} - 4 \cdot 15 \cdot 0 = 5

t_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 15}

Separate the solutions

t_{1} = \frac{- 5 + 5}{2 \cdot 15}, t_{2} = \frac{- 5 - 5}{2 \cdot 15}

t = \frac{- 5 + 5}{2 \cdot 15} : 0

t = \frac{- 5 - 5}{2 \cdot 15} : - \frac{1}{3}

The solutions to the quadratic equation are:

t = 0, t = - \frac{1}{3}

9 x^{2} - 25 z^{2}

x^{2} + 5 x = - 4

9 x^{2} - 3 x = 1

9 + 6 i

What are the solutions to the equation 15t^2+5t=0 ?
The solutions to the equation 15t^2+5t=0 are t=0,t=-1/3
Find the zeros of 15t^2+5t=0
The zeros of 15t^2+5t=0 are t=0,t=-1/3