What are the solutions to the equation 5(x+3)^2+9(x+3)=2 ?

The solutions to the equation 5(x+3)^2+9(x+3)=2 are x=-14/5 ,x=-5

Find the zeros of 5(x+3)^2+9(x+3)=2

The zeros of 5(x+3)^2+9(x+3)=2 are x=-14/5 ,x=-5

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5 (x + 3)^{2} + 9 (x + 3) = 2

x = - \frac{14}{5}, x = - 5

Decimal Notation

x = - 2.8, x = - 5

Solution steps

5 (x + 3)^{2} + 9 (x + 3) = 2

Expand

5 (x + 3)^{2} + 9 (x + 3) : 5 x^{2} + 39 x + 72

5 x^{2} + 39 x + 72 = 2

Move

2

to the left side

5 x^{2} + 39 x + 70 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 39 \pm 3 9 ^{2} - 4 \cdot 5 \cdot 70}{2 \cdot 5}

3 9^{2} - 4 \cdot 5 \cdot 70 = 11

x_{1, 2} = \frac{- 39 \pm 11}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 39 + 11}{2 \cdot 5}, x_{2} = \frac{- 39 - 11}{2 \cdot 5}

x = \frac{- 39 + 11}{2 \cdot 5} : - \frac{14}{5}

x = \frac{- 39 - 11}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

x = - \frac{14}{5}, x = - 5

- 5 a + 3 b + 8 a

∣ 4 x - 10 ∣ = 25 - x

∣ 4 x + 2 ∣ = ∣ 7 x - 2 ∣

x^{3} - 4 x^{2} - 16 x + 64

\frac{8}{3} - \frac{2}{7}

What are the solutions to the equation 5(x+3)^2+9(x+3)=2 ?
The solutions to the equation 5(x+3)^2+9(x+3)=2 are x=-14/5 ,x=-5
Find the zeros of 5(x+3)^2+9(x+3)=2
The zeros of 5(x+3)^2+9(x+3)=2 are x=-14/5 ,x=-5