What are the solutions to the equation 6m^2+5m-3=0 ?

The solutions to the equation 6m^2+5m-3=0 are m=(-5+sqrt(97))/(12),m=(-5-sqrt(97))/(12)

Find the zeros of 6m^2+5m-3=0

The zeros of 6m^2+5m-3=0 are m=(-5+sqrt(97))/(12),m=(-5-sqrt(97))/(12)

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6 m^{2} + 5 m - 3 = 0

m = \frac{- 5 + 97}{12}, m = \frac{- 5 - 97}{12}

Decimal Notation

m = 0.40407 \dots, m = - 1.23740 \dots

Solution steps

6 m^{2} + 5 m - 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

5^{2} - 4 \cdot 6 (- 3) = 97

m_{1, 2} = \frac{- 5 \pm 97}{2 \cdot 6}

Separate the solutions

m_{1} = \frac{- 5 + 97}{2 \cdot 6}, m_{2} = \frac{- 5 - 97}{2 \cdot 6}

m = \frac{- 5 + 97}{2 \cdot 6} : \frac{- 5 + 97}{12}

m = \frac{- 5 - 97}{2 \cdot 6} : \frac{- 5 - 97}{12}

The solutions to the quadratic equation are:

m = \frac{- 5 + 97}{12}, m = \frac{- 5 - 97}{12}

\frac{x}{9} + 6 = 8

8 a + 10 \leq 12 a - 18

y^{2} - 20 y + 100

4 ∣ x + 10 ∣ > 8

x = 2 x - 2

What are the solutions to the equation 6m^2+5m-3=0 ?
The solutions to the equation 6m^2+5m-3=0 are m=(-5+sqrt(97))/(12),m=(-5-sqrt(97))/(12)
Find the zeros of 6m^2+5m-3=0
The zeros of 6m^2+5m-3=0 are m=(-5+sqrt(97))/(12),m=(-5-sqrt(97))/(12)