What are the solutions to the equation 15x^2+31x=-10 ?

The solutions to the equation 15x^2+31x=-10 are x=-2/5 ,x=-5/3

Find the zeros of 15x^2+31x=-10

The zeros of 15x^2+31x=-10 are x=-2/5 ,x=-5/3

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15 x^{2} + 31 x = - 10

x = - \frac{2}{5}, x = - \frac{5}{3}

Decimal Notation

x = - 0.4, x = - 1.66666 \dots

Solution steps

15 x^{2} + 31 x = - 10

Move

10

to the left side

15 x^{2} + 31 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 31 \pm 3 1 ^{2} - 4 \cdot 15 \cdot 10}{2 \cdot 15}

3 1^{2} - 4 \cdot 15 \cdot 10 = 19

x_{1, 2} = \frac{- 31 \pm 19}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 31 + 19}{2 \cdot 15}, x_{2} = \frac{- 31 - 19}{2 \cdot 15}

x = \frac{- 31 + 19}{2 \cdot 15} : - \frac{2}{5}

x = \frac{- 31 - 19}{2 \cdot 15} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = - \frac{2}{5}, x = - \frac{5}{3}

∣ 3 x - 6 ∣ > 9

(\frac{3}{2})^{- 2}

2 \frac{1}{2}

(\frac{15}{16})^{2}

∣ 5 x + 3 ∣ < 7

What are the solutions to the equation 15x^2+31x=-10 ?
The solutions to the equation 15x^2+31x=-10 are x=-2/5 ,x=-5/3
Find the zeros of 15x^2+31x=-10
The zeros of 15x^2+31x=-10 are x=-2/5 ,x=-5/3