What are the solutions to the equation 6^2+2^2=c^2 ?

The solutions to the equation 6^2+2^2=c^2 are c=2sqrt(10),c=-2sqrt(10)

Find the zeros of 6^2+2^2=c^2

The zeros of 6^2+2^2=c^2 are c=2sqrt(10),c=-2sqrt(10)

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6^{2} + 2^{2} = c^{2}

c = 210, c = - 210

Decimal Notation

c = 6.32455 \dots, c = - 6.32455 \dots

Solution steps

6^{2} + 2^{2} = c^{2}

Switch sides

c^{2} = 6^{2} + 2^{2}

Simplify

6^{2} + 2^{2} : 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 40, c = - 40

40 = 210

- 40 = - 210

c = 210, c = - 210

140 + x = 180

m^{2} + 7 = 88

6 r^{2} + 11 r p - 35 p^{2}

5^{4} \cdot 5^{2}

2 - x = 4

What are the solutions to the equation 6^2+2^2=c^2 ?
The solutions to the equation 6^2+2^2=c^2 are c=2sqrt(10),c=-2sqrt(10)
Find the zeros of 6^2+2^2=c^2
The zeros of 6^2+2^2=c^2 are c=2sqrt(10),c=-2sqrt(10)