What are the solutions to the equation 6(x-3)^2-13(x-3)-5=0 ?

The solutions to the equation 6(x-3)^2-13(x-3)-5=0 are x= 11/2 ,x= 8/3

Find the zeros of 6(x-3)^2-13(x-3)-5=0

The zeros of 6(x-3)^2-13(x-3)-5=0 are x= 11/2 ,x= 8/3

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6 (x - 3)^{2} - 13 (x - 3) - 5 = 0

x = \frac{11}{2}, x = \frac{8}{3}

Decimal Notation

x = 5.5, x = 2.66666 \dots

Solution steps

6 (x - 3)^{2} - 13 (x - 3) - 5 = 0

Expand

6 (x - 3)^{2} - 13 (x - 3) - 5 : 6 x^{2} - 49 x + 88

6 x^{2} - 49 x + 88 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 49 ) \pm ( - 49 ) ^{2} - 4 \cdot 6 \cdot 88}{2 \cdot 6}

(- 49)^{2} - 4 \cdot 6 \cdot 88 = 17

x_{1, 2} = \frac{- ( - 49 ) \pm 17}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 49 ) + 17}{2 \cdot 6}, x_{2} = \frac{- ( - 49 ) - 17}{2 \cdot 6}

x = \frac{- ( - 49 ) + 17}{2 \cdot 6} : \frac{11}{2}

x = \frac{- ( - 49 ) - 17}{2 \cdot 6} : \frac{8}{3}

The solutions to the quadratic equation are:

x = \frac{11}{2}, x = \frac{8}{3}

\frac{- 1 x - 3}{- 2} = 7

9 x^{2} + 36 x - 45

\frac{x + 4}{5} = \frac{x + 4}{10}

3 2^{\frac{7}{5}}

- 4 (2 c + 7) = c^{2} + 17 c + 7

What are the solutions to the equation 6(x-3)^2-13(x-3)-5=0 ?
The solutions to the equation 6(x-3)^2-13(x-3)-5=0 are x= 11/2 ,x= 8/3
Find the zeros of 6(x-3)^2-13(x-3)-5=0
The zeros of 6(x-3)^2-13(x-3)-5=0 are x= 11/2 ,x= 8/3