What are the solutions to the equation -3x^2-0.75x+6=0 ?

The solutions to the equation -3x^2-0.75x+6=0 are x=-(1+sqrt(129))/8 ,x=(sqrt(129)-1)/8

Find the zeros of -3x^2-0.75x+6=0

The zeros of -3x^2-0.75x+6=0 are x=-(1+sqrt(129))/8 ,x=(sqrt(129)-1)/8

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- 3 x^{2} - 0.75 x + 6 = 0

x = - \frac{1 + 129}{8}, x = \frac{129 - 1}{8}

Solution steps

- 3 x^{2} - 0.75 x + 6 = 0

Multiply both sides by

100

- 300 x^{2} - 75 x + 600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 75 ) \pm ( - 75 ) ^{2} - 4 ( - 300 ) \cdot 600}{2 ( - 300 )}

(- 75)^{2} - 4 (- 300) \cdot 600 = 75129

x_{1, 2} = \frac{- ( - 75 ) \pm 75 129}{2 ( - 300 )}

Separate the solutions

x_{1} = \frac{- ( - 75 ) + 75 129}{2 ( - 300 )}, x_{2} = \frac{- ( - 75 ) - 75 129}{2 ( - 300 )}

x = \frac{- ( - 75 ) + 75 129}{2 ( - 300 )} : - \frac{1 + 129}{8}

x = \frac{- ( - 75 ) - 75 129}{2 ( - 300 )} : \frac{129 - 1}{8}

The solutions to the quadratic equation are:

x = - \frac{1 + 129}{8}, x = \frac{129 - 1}{8}

\frac{x ^{- 1} y ^{2}}{x ^{2} y ^{- 1}}

m^{2} + 16 m + 64

5 6^{2} + x^{2} = 6 5^{2}

\frac{1}{x + 4} \leq \frac{- 2}{1 - x}

16 a + 6

What are the solutions to the equation -3x^2-0.75x+6=0 ?
The solutions to the equation -3x^2-0.75x+6=0 are x=-(1+sqrt(129))/8 ,x=(sqrt(129)-1)/8
Find the zeros of -3x^2-0.75x+6=0
The zeros of -3x^2-0.75x+6=0 are x=-(1+sqrt(129))/8 ,x=(sqrt(129)-1)/8