What are the solutions to the equation 5x^2+6x-63=0 ?

The solutions to the equation 5x^2+6x-63=0 are x=3,x=-21/5

Find the zeros of 5x^2+6x-63=0

The zeros of 5x^2+6x-63=0 are x=3,x=-21/5

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5 x^{2} + 6 x - 63 = 0

x = 3, x = - \frac{21}{5}

Decimal Notation

x = 3, x = - 4.2

Solution steps

5 x^{2} + 6 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 5 ( - 63 )}{2 \cdot 5}

6^{2} - 4 \cdot 5 (- 63) = 36

x_{1, 2} = \frac{- 6 \pm 36}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 6 + 36}{2 \cdot 5}, x_{2} = \frac{- 6 - 36}{2 \cdot 5}

x = \frac{- 6 + 36}{2 \cdot 5} : 3

x = \frac{- 6 - 36}{2 \cdot 5} : - \frac{21}{5}

The solutions to the quadratic equation are:

x = 3, x = - \frac{21}{5}

u^{2} = 4

w^{2} - 17 w + 72

x^{3} + 12 x^{2} + 9 x - 22

(x^{4} y^{2})^{\frac{1}{2}}

x (2 x - 2) = 760

What are the solutions to the equation 5x^2+6x-63=0 ?
The solutions to the equation 5x^2+6x-63=0 are x=3,x=-21/5
Find the zeros of 5x^2+6x-63=0
The zeros of 5x^2+6x-63=0 are x=3,x=-21/5