What are the solutions to the equation x^2+14x+8=0 ?

The solutions to the equation x^2+14x+8=0 are x=-7+sqrt(41),x=-7-sqrt(41)

Find the zeros of x^2+14x+8=0

The zeros of x^2+14x+8=0 are x=-7+sqrt(41),x=-7-sqrt(41)

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x^{2} + 14 x + 8 = 0

x = - 7 + 41, x = - 7 - 41

Solution steps

x^{2} + 14 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 8 = 241

x_{1, 2} = \frac{- 14 \pm 2 41}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 41}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 41}{2 \cdot 1}

x = \frac{- 14 + 2 41}{2 \cdot 1} : - 7 + 41

x = \frac{- 14 - 2 41}{2 \cdot 1} : - 7 - 41

The solutions to the quadratic equation are:

x = - 7 + 41, x = - 7 - 41

x^{2} - 4 x = 77

\frac{1}{3}

42 x^{2} - 69 x + 20 = 7 x^{2} - 8

5 (6 - 3 Y) + 2 Y = 13

c^{2} - 100

What are the solutions to the equation x^2+14x+8=0 ?
The solutions to the equation x^2+14x+8=0 are x=-7+sqrt(41),x=-7-sqrt(41)
Find the zeros of x^2+14x+8=0
The zeros of x^2+14x+8=0 are x=-7+sqrt(41),x=-7-sqrt(41)