What are the solutions to the equation 5-2x^2=-3 ?

The solutions to the equation 5-2x^2=-3 are x=2,x=-2

Find the zeros of 5-2x^2=-3

The zeros of 5-2x^2=-3 are x=2,x=-2

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5 - 2 x^{2} = - 3

x = 2, x = - 2

Solution steps

5 - 2 x^{2} = - 3

Move

5

to the right side

- 2 x^{2} = - 8

Divide both sides by

- 2

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

(x - 1)^{2} = 1

6 k^{2} - 7 k - 20

\frac{4}{5} \cdot 2

3 x^{2} + 6 x - 9

- 8 < 7 - 5 x \leq 87

What are the solutions to the equation 5-2x^2=-3 ?
The solutions to the equation 5-2x^2=-3 are x=2,x=-2
Find the zeros of 5-2x^2=-3
The zeros of 5-2x^2=-3 are x=2,x=-2