What are the solutions to the equation 2m^2+2m-12=0 ?

The solutions to the equation 2m^2+2m-12=0 are m=2,m=-3

Find the zeros of 2m^2+2m-12=0

The zeros of 2m^2+2m-12=0 are m=2,m=-3

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2 m^{2} + 2 m - 12 = 0

m = 2, m = - 3

Solution steps

2 m^{2} + 2 m - 12 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 12) = 10

m_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- 2 + 10}{2 \cdot 2}, m_{2} = \frac{- 2 - 10}{2 \cdot 2}

m = \frac{- 2 + 10}{2 \cdot 2} : 2

m = \frac{- 2 - 10}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

m = 2, m = - 3

\frac{18}{81}

x^{2} + 1 = 2 x - 3

- 3 (3 h - 2) \leq - 7 h - 10

x^{3} + 5 x^{2} + x + 5

5 x^{2} - 15 x - 50 = 0

What are the solutions to the equation 2m^2+2m-12=0 ?
The solutions to the equation 2m^2+2m-12=0 are m=2,m=-3
Find the zeros of 2m^2+2m-12=0
The zeros of 2m^2+2m-12=0 are m=2,m=-3