What is the d/(dz)((2/3 zl-m) 3/4) ?

The d/(dz)((2/3 zl-m) 3/4) is l/2

What is the first d/(dz)((2/3 zl-m) 3/4) ?

The first d/(dz)((2/3 zl-m) 3/4) is l/2

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\frac{d}{d z} ((\frac{2}{3} z l - m) \frac{3}{4})

\frac{l}{2}

Solution steps

\frac{d}{d z} ((\frac{2}{3} z l - m) \frac{3}{4})

Simplify

(\frac{2}{3} z l - m) \frac{3}{4} : \frac{l z}{2} - \frac{3 m}{4}

= \frac{d}{d z} (\frac{l z}{2} - \frac{3 m}{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d z} (\frac{l z}{2}) - \frac{d}{d z} (\frac{3 m}{4})

\frac{d}{d z} (\frac{l z}{2}) = \frac{l}{2}

\frac{d}{d z} (\frac{3 m}{4}) = 0

= \frac{l}{2} - 0

Simplify

= \frac{l}{2}

3 - \frac{6}{4}

5 x - 20 x^{7}

x^{2} - 10 x - 39 = 0

x^{2} - 2 x - 5 = 0

2 x^{2} - 3 x - 9 = 0

What is the d/(dz)((2/3 zl-m) 3/4) ?
The d/(dz)((2/3 zl-m) 3/4) is l/2
What is the first d/(dz)((2/3 zl-m) 3/4) ?
The first d/(dz)((2/3 zl-m) 3/4) is l/2