What are the solutions to the equation 12x^2+32x=-5 ?

The solutions to the equation 12x^2+32x=-5 are x=-1/6 ,x=-5/2

Find the zeros of 12x^2+32x=-5

The zeros of 12x^2+32x=-5 are x=-1/6 ,x=-5/2

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12 x^{2} + 32 x = - 5

x = - \frac{1}{6}, x = - \frac{5}{2}

Solution steps

12 x^{2} + 32 x = - 5

Move

5

to the left side

12 x^{2} + 32 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 12 \cdot 5}{2 \cdot 12}

3 2^{2} - 4 \cdot 12 \cdot 5 = 28

x_{1, 2} = \frac{- 32 \pm 28}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 32 + 28}{2 \cdot 12}, x_{2} = \frac{- 32 - 28}{2 \cdot 12}

x = \frac{- 32 + 28}{2 \cdot 12} : - \frac{1}{6}

x = \frac{- 32 - 28}{2 \cdot 12} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{6}, x = - \frac{5}{2}

f^{2} - 63 = 81

3 2 a - 3 2 b

18 x^{2} y - 42 x^{2} - 27 y + 63

3 x^{2} + 5 x

\frac{x}{2} = 60

What are the solutions to the equation 12x^2+32x=-5 ?
The solutions to the equation 12x^2+32x=-5 are x=-1/6 ,x=-5/2
Find the zeros of 12x^2+32x=-5
The zeros of 12x^2+32x=-5 are x=-1/6 ,x=-5/2