What are the solutions to the equation 2k^2+9k=-7 ?

The solutions to the equation 2k^2+9k=-7 are k=-1,k=-7/2

Find the zeros of 2k^2+9k=-7

The zeros of 2k^2+9k=-7 are k=-1,k=-7/2

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2 k^{2} + 9 k = - 7

k = - 1, k = - \frac{7}{2}

Solution steps

2 k^{2} + 9 k = - 7

Move

7

to the left side

2 k^{2} + 9 k + 7 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

9^{2} - 4 \cdot 2 \cdot 7 = 5

k_{1, 2} = \frac{- 9 \pm 5}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- 9 + 5}{2 \cdot 2}, k_{2} = \frac{- 9 - 5}{2 \cdot 2}

k = \frac{- 9 + 5}{2 \cdot 2} : - 1

k = \frac{- 9 - 5}{2 \cdot 2} : - \frac{7}{2}

The solutions to the quadratic equation are:

k = - 1, k = - \frac{7}{2}

\frac{1}{4} - \frac{1}{3} x = \frac{1}{3}

\frac{∣ x + 2 ∣}{3} = - 3

(2 x - 1)^{2} = 9

9 x^{4} - 16 y^{4}

8 (s + 3) = 72

What are the solutions to the equation 2k^2+9k=-7 ?
The solutions to the equation 2k^2+9k=-7 are k=-1,k=-7/2
Find the zeros of 2k^2+9k=-7
The zeros of 2k^2+9k=-7 are k=-1,k=-7/2