What is factor 4a^2+4ab+b^2 ?

The solution to factor 4a^2+4ab+b^2 is (2a+b)^2

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factor 4a^2+4ab+b^2

factor

4 a^{2} + 4 ab + b^{2}

(2 a + b)^{2}

Solution steps

4 a^{2} + 4 ab + b^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 a^{2} = (2 a)^{2}

4 ab = 2 \cdot 2 ab

= (2 a)^{2} + 2 \cdot 2 ab + b^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(2 a)^{2} + 2 \cdot 2 ab + b^{2} = (2 a + b)^{2}

= (2 a + b)^{2}

(i)^{2}

(- x^{2} - 2 x + 8) = 0

\frac{1}{3} \cdot 18

\frac{3}{5} (\frac{x - 1}{3} + 1) + x = \frac{3}{4} (x - \frac{2}{3})

\frac{1}{3} π \cdot 2. 7^{2} \cdot 5