What are the solutions to the equation 2x^2+50=0 ?

The solutions to the equation 2x^2+50=0 are x=5i,x=-5i

Find the zeros of 2x^2+50=0

The zeros of 2x^2+50=0 are x=5i,x=-5i

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2 x^{2} + 50 = 0

x = 5 i, x = - 5 i

Solution steps

2 x^{2} + 50 = 0

Move

50

to the right side

2 x^{2} = - 50

Divide both sides by

2

x^{2} = - 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 25, x = - - 25

- 25 = 5 i

- - 25 = - 5 i

x = 5 i, x = - 5 i

4 x^{2} + 9 x + 2 < 0

- x^{2} - 2 x + 1 = 0

ln (x - 2) - 3 ln (2) = 2

x^{2} - 1 \leq ∣ x + 1 ∣

4 \cdot \frac{5}{6}

What are the solutions to the equation 2x^2+50=0 ?
The solutions to the equation 2x^2+50=0 are x=5i,x=-5i
Find the zeros of 2x^2+50=0
The zeros of 2x^2+50=0 are x=5i,x=-5i