What is (2^3+2^{-3})/(4^3+1) ?

The solution to (2^3+2^{-3})/(4^3+1) is 1/8

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simplify (2^3+2^{-3})/(4^3+1)

simplify

\frac{2 ^{3} + 2 ^{- 3}}{4 ^{3} + 1}

\frac{1}{8}

Decimal Notation

0.125

Solution steps

\frac{2 ^{3} + 2 ^{- 3}}{4 ^{3} + 1}

Simplify

2^{3} + 2^{- 3} : \frac{65}{8}

= \frac{\frac{65}{8}}{4 ^{3} + 1}

4^{3} + 1 = 65

= \frac{\frac{65}{8}}{65}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{65}{8 \cdot 65}

Cancel the common factor:

65

= \frac{1}{8}

∣ 6 x + 5 ∣ = 8

∣ k + 1 ∣ + 2 = 8

9 + 12 n

\frac{2 - 3 x}{5} \geq 2

\frac{4}{7} + \frac{2}{3}