What are the solutions to the equation -6x^2-4x+4=0 ?

The solutions to the equation -6x^2-4x+4=0 are x=-(1+sqrt(7))/3 ,x=(sqrt(7)-1)/3

Find the zeros of -6x^2-4x+4=0

The zeros of -6x^2-4x+4=0 are x=-(1+sqrt(7))/3 ,x=(sqrt(7)-1)/3

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- 6 x^{2} - 4 x + 4 = 0

x = - \frac{1 + 7}{3}, x = \frac{7 - 1}{3}

Solution steps

- 6 x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 6 ) \cdot 4}{2 ( - 6 )}

(- 4)^{2} - 4 (- 6) \cdot 4 = 47

x_{1, 2} = \frac{- ( - 4 ) \pm 4 7}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 7}{2 ( - 6 )}, x_{2} = \frac{- ( - 4 ) - 4 7}{2 ( - 6 )}

x = \frac{- ( - 4 ) + 4 7}{2 ( - 6 )} : - \frac{1 + 7}{3}

x = \frac{- ( - 4 ) - 4 7}{2 ( - 6 )} : \frac{7 - 1}{3}

The solutions to the quadratic equation are:

x = - \frac{1 + 7}{3}, x = \frac{7 - 1}{3}

- 1 - 2

3 x + 6 \geq - 15

\frac{9}{64}

y^{2} - 4 y + 4 = 0

\frac{8 - 4 x}{10} = 4 + 2 x

What are the solutions to the equation -6x^2-4x+4=0 ?
The solutions to the equation -6x^2-4x+4=0 are x=-(1+sqrt(7))/3 ,x=(sqrt(7)-1)/3
Find the zeros of -6x^2-4x+4=0
The zeros of -6x^2-4x+4=0 are x=-(1+sqrt(7))/3 ,x=(sqrt(7)-1)/3