What is factor 625t^2+100t^1+4 ?

The solution to factor 625t^2+100t^1+4 is (25t+2)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 625t^2+100t^1+4

factor

625 t^{2} + 100 t^{1} + 4

(25 t + 2)^{2}

Solution steps

625 t^{2} + 100 t^{1} + 4

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

625 t^{2} = (25 t)^{2}

4 = 2^{2}

100 t = 2 \cdot 25 t \cdot 2

= (25 t)^{2} + 2 \cdot 25 t \cdot 2 + 2^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(25 t)^{2} + 2 \cdot 25 t \cdot 2 + 2^{2} = (25 t + 2)^{2}

= (25 t + 2)^{2}

a^{4} + 4 a^{2} m + 4 m^{2}

\frac{2 ^{3} + 4 ^{2}}{( \frac{2}{3} ) ^{2}}

x^{4} + x - 2

5 x^{2} - 77 > x^{2} + 37 x

\frac{12}{8} = \frac{n}{4}

What is factor 625t^2+100t^1+4 ?
The solution to factor 625t^2+100t^1+4 is (25t+2)^2