What is the answer to 9c(c-11)+10(5c-3)=3c(c+5)+c(6c-3)-30 ?

The answer to 9c(c-11)+10(5c-3)=3c(c+5)+c(6c-3)-30 is c=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9c(c-11)+10(5c-3)=3c(c+5)+c(6c-3)-30

9 c (c - 11) + 10 (5 c - 3) = 3 c (c + 5) + c (6 c - 3) - 30

c = 0

Solution steps

9 c (c - 11) + 10 (5 c - 3) = 3 c (c + 5) + c (6 c - 3) - 30

Expand

9 c (c - 11) : 9 c^{2} - 99 c

9 c^{2} - 99 c + 10 (5 c - 3) = 3 c (c + 5) + c (6 c - 3) - 30

Expand

10 (5 c - 3) : 50 c - 30

9 c^{2} - 99 c + 50 c - 30 = 3 c (c + 5) + c (6 c - 3) - 30

Add similar elements:

- 99 c + 50 c = - 49 c

9 c^{2} - 49 c - 30 = 3 c (c + 5) + c (6 c - 3) - 30

Expand

3 c (c + 5) + c (6 c - 3) - 30 : 9 c^{2} + 12 c - 30

9 c^{2} - 49 c - 30 = 9 c^{2} + 12 c - 30

Move

30

to the right side

9 c^{2} - 49 c = 9 c^{2} + 12 c

Subtract

9 c^{2} + 12 c

from both sides

9 c^{2} - 49 c - (9 c^{2} + 12 c) = 9 c^{2} + 12 c - (9 c^{2} + 12 c)

Simplify

- 61 c = 0

Divide both sides by

- 61

c = 0

x^{2} - 15 x + 54 > 0

- 3 z^{2} - 4 z + 1 = 0

\frac{3 ( 4 - z )}{2} = - z

e^{x} \cdot e^{y}

\frac{8}{3} s = - 9 + 7

What is the answer to 9c(c-11)+10(5c-3)=3c(c+5)+c(6c-3)-30 ?
The answer to 9c(c-11)+10(5c-3)=3c(c+5)+c(6c-3)-30 is c=0
Solve for c: 9c(c-11)+10(5c-3)=3c(c+5)+c(6c-3)-30
The solution is c=0