What are the solutions to the equation p^2+2p(0.06)+0.36=1 ?

The solutions to the equation p^2+2p(0.06)+0.36=1 are p=(-3+sqrt(1609))/(50),p=-(3+sqrt(1609))/(50)

Find the zeros of p^2+2p(0.06)+0.36=1

The zeros of p^2+2p(0.06)+0.36=1 are p=(-3+sqrt(1609))/(50),p=-(3+sqrt(1609))/(50)

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p^{2} + 2 p (0.06) + 0.36 = 1

p = \frac{- 3 + 1609}{50}, p = - \frac{3 + 1609}{50}

Decimal Notation

p = 0.74224 \dots, p = - 0.86224 \dots

Solution steps

p^{2} + 2 p (0.06) + 0.36 = 1

Multiply both sides by

100

100 p^{2} + 12 p + 36 = 100

Move

100

to the left side

100 p^{2} + 12 p - 64 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 100 ( - 64 )}{2 \cdot 100}

1 2^{2} - 4 \cdot 100 (- 64) = 41609

p_{1, 2} = \frac{- 12 \pm 4 1609}{2 \cdot 100}

Separate the solutions

p_{1} = \frac{- 12 + 4 1609}{2 \cdot 100}, p_{2} = \frac{- 12 - 4 1609}{2 \cdot 100}

p = \frac{- 12 + 4 1609}{2 \cdot 100} : \frac{- 3 + 1609}{50}

p = \frac{- 12 - 4 1609}{2 \cdot 100} : - \frac{3 + 1609}{50}

The solutions to the quadratic equation are:

p = \frac{- 3 + 1609}{50}, p = - \frac{3 + 1609}{50}

15 x^{2} + 29 x + 12

- 1 \leq x - 2 \leq 4

4 x - 6 = 3 x

\frac{2 a ^{- 1} b ^{4} \cdot 2 a ^{0} b ^{0}}{b ^{4}}

n^{2} - 7 n = 0

What are the solutions to the equation p^2+2p(0.06)+0.36=1 ?
The solutions to the equation p^2+2p(0.06)+0.36=1 are p=(-3+sqrt(1609))/(50),p=-(3+sqrt(1609))/(50)
Find the zeros of p^2+2p(0.06)+0.36=1
The zeros of p^2+2p(0.06)+0.36=1 are p=(-3+sqrt(1609))/(50),p=-(3+sqrt(1609))/(50)